How many Error Reports did MS get off Vista?

[Moo]

Take a guess at it, Ill give out the answer and Note this is a joke/trick question/ dick/ riddle/ whatever the fuckk you want to call it

[USOLA]

dont you have anything more important to post?

[Moo]

dont you have anything more important to post?

LOLim a spammer all things are equal in importance, unless its not really spam

[peow130]

over 9000

[Omega]

I have the correct answer. The number of reports is x, where x is greater than or equal to zero.

[peow130]

Y=x^v

y is the number of reports
x is the number of people sending reports
v is the average number of reports per person.

[Omega]

Y=x^v

y is the number of reports
x is the number of people sending reports
v is the average number of reports per person.

If one person sends in 5 reports, Y = 5. x = 1, and v = 5.

1^5 = 1; 1 != 5.

If two people send in 10 reports, Y = 10. x = 2, and v = 5.

2^5 = 32; 32 != 10.

You fail. Hard.

[Sexacutioner]

yeah but most reports people send are because their fuckin morons, i havent ever had a problem with any windows i just didnt like how vista ran but i got that shit all fixed up quick fast and in a hurry O_O

[peow130]

Y=x^v

y is the number of reports
x is the number of people sending reports
v is the average number of reports per person.

If one person sends in 5 reports, Y = 5. x = 1, and v = 5.

1^5 = 1; 1 != 5.

If two people send in 10 reports, Y = 10. x = 2, and v = 5.

2^5 = 32; 32 != 10.

You fail. Hard.

nup.

[Ghost]

Honestly, I don't think MS gets very many error reports from any of their operating systems since the feature was added. Anyone in their right mind goes through the following thought process when that window pops up: "What the fuck, my shit just crashed. Hmmm... report or close? Fuck Microsoft, even if I do report this shit it's not like they're gonna do anything about it anyway. *close*"

[Sexacutioner]

yeah ive never sent an error report and its mostly when ee crashes, thats prob 90% of the problems in my backlogs every time i delete them lol

[Moo]

Well Since Omega is being a big nerd the vairable "v" is not supposed to be decided it gets reflected upon y and x and since Peow is the only one who answered with Over 9000 i guess he wins even though he was wrong. The real answer is Vista never got any error reports, it failed so hard it cant send error reports, it only makes you think microsoft will do something about it

[X warrior411]

viewtopic.php?f=12&t=1456&p=8358&hilit=vista#p8358
Old thread with Vista joke pictures.

[Omega]

Well Since Omega is being a big nerd the vairable "v" is not supposed to be decided it gets reflected upon y and x

Are you retarded? Actually, no need to answer that.

"Y=x^v

y is the number of reports
x is the number of people sending reports
v is the average number of reports per person."

If v is the average number of reports per person, we merely need to average the number of reports per person. We don't fucking "decide" anything, we can calculate it. If only 3 people, Persons A through C send reports, and Person A sends 5 reports, person B sends 3, and person C sends 7 reports, then average reports per person = v = (5+3+10)/3 = 15/3 = 5

The number of people sending reports in that case is obviously three.

The number of reports sent as per the equation would then be 243. Of course, given the information needed to calculate v we can also determine that the number of reports is in fact 15. That's an error of 1,520 percent. To get a correct value for Y, we'd need to use a v value that is ln(15)/ln(3). That value is nonsensical and wrong, because we have the data needed to find the average number of reports per person in this instance, and it's certainly fucking not ln(15)/ln(3).

Additionally, if v was the variable you wanted to find out, and not y, the equation would be arranged so that v is solved for, NOT ARRANGED HOW IT CURRENTLY IS. That is, it'd be v = ln(Y)/ln(x). Of course, using that wouldn't help us at all, since the value for v will not always yield the true value for v (I'm too lazy to figure out whether or not you could even *ever* get a sensible true value for v).

***THE POINT IS, THE EQUATION FAILS, AND ANYONE CAN SEE IT DOES***

[Ghost]

Well Since Omega is being a big nerd the vairable "v" is not supposed to be decided it gets reflected upon y and x

Are you retarded? Actually, no need to answer that.

"Y=x^v

y is the number of reports
x is the number of people sending reports
v is the average number of reports per person."

If v is the average number of reports per person, we merely need to average the number of reports per person. We don't fucking "decide" anything, we can calculate it. If only 3 people, Persons A through C send reports, and Person A sends 5 reports, person B sends 3, and person C sends 7 reports, then average reports per person = v = (5+3+10)/3 = 15/3 = 5

The number of people sending reports in that case is obviously three.

The number of reports sent as per the equation would then be 243. Of course, given the information needed to calculate v we can also determine that the number of reports is in fact 15. That's an error of 1,520 percent. To get a correct value for Y, we'd need to use a v value that is ln(15)/ln(3). That value is nonsensical and wrong, because we have the data needed to find the average number of reports per person in this instance, and it's certainly fucking not ln(15)/ln(3).

Additionally, if v was the variable you wanted to find out, and not y, the equation would be arranged so that v is solved for, NOT ARRANGED HOW IT CURRENTLY IS. That is, it'd be v = ln(Y)/ln(x). Of course, using that wouldn't help us at all, since the value for v will not always yield the true value for v (I'm too lazy to figure out whether or not you could even *ever* get a sensible true value for v).

***THE POINT IS, THE EQUATION FAILS, AND ANYONE CAN SEE IT DOES***