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1 x 8 + 1 = 9
12 x 8 + 2 = 98
123 x 8 + 3 = 987
1234 x 8 + 4 = 9876
12345 x 8 + 5 = 98765
123456 x 8 + 6 = 987654
1234567 x 8 + 7 = 9876543
12345678 x 8 + 8 = 98765432
123456789 x 8 + 9 = 987654321


1 x 9 + 2 = 11
12 x 9 + 3 = 111
123 x 9 + 4 = 1111
1234 x 9 + 5 = 11111
12345 x 9 + 6 = 111111
123456 x 9 + 7 = 1111111
1234567 x 9 + 8 = 11111111
12345678 x 9 + 9 = 111111111
123456789 x 9 +10= 1111111111

9 x 9 + 7 = 88
98 x 9 + 6 = 888
987 x 9 + 5 = 8888
9876 x 9 + 4 = 88888
98765 x 9 + 3 = 888888
987654 x 9 + 2 = 8888888
9876543 x 9 + 1 = 88888888
98765432 x 9 + 0 = 888888888

1 x 1 = 1
11 x 11 = 121
111 x 111 = 12321
1111 x 1111 = 1234321
11111 x 11111 = 123454321
111111 x 111111 = 12345654321
1111111 x 1111111 = 1234567654321
11111111 x 11111111 = 123456787654321
111111111 x 111111111= 12345678987654321

Cool math, cool numbers I thought

Indica, you possibly cannot made these maths yourself O_O!

lightnessking wrote:Indica, you possibly cannot made these maths yourself O_O!

Heck no, i suck at Math. I came across them on the web and thought they were cool.

Given: a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
(a+b)=b
a+a=a
2a=a
2=1

THIS IS NAZI MATHS!!!!

9 x 9 + 7 = 88
98 x 9 + 6 = 888
987 x 9 + 5 = 8888
9876 x 9 + 4 = 88888
98765 x 9 + 3 = 888888
987654 x 9 + 2 = 8888888
9876543 x 9 + 1 = 88888888
98765432 x 9 + 0 = 888888888

d-dog wrote:Given: a=b
a^2=ab
a^2-b^2=ab-b^2
(a+b)(a-b)=b(a-b)
(a+b)=b
a+a=a
2a=a
2=1

This is obviously isn't right because in order for lines 3 and after to be true, a=b MUST equal 0. When moving from line 3 to 4 and from line 6 to 7 you would be dividing by zero, which is undefined. This would stop the proof before being able to make the conclusion 2=1.

i = √-1

Yay for Imaginary Numbers....o_o.

1/3 = 3.3 repeating
3.3 x 3 = 9.9 Repeating
1/3 x3 = 1
9.9 repeating = 1

Way to ruin a genius's thread Moo.

P-51 wrote:Way to ruin a genius's thread Moo.

Name 1 that divided by 0, or are you just still butthurt?

Well for me discovering these math's was quite fascinating, I mean
just look at that perfect symetry and logic
Was wondering if anyone else was aware, or had seen these
calculations/formulations before ?

e^(pi*sqrt(-1)) = -1

Let it blow your mind that when you raise e to pi times animaginary number you get a real result.

ITT: Troll physics

peow130 wrote:ITT: Troll physics

Now we're talking

Omega wrote:e^(pi*sqrt(-1)) = -1

Let it blow your mind that when you raise e to pi times animaginary number you get a real result.

i^2 = -1...
lol..